The maximum value of sin x . cos x is
(A) 1/4 (B) 1/2
(C) √2 (D) 2 √2
This question is similar to Ex 6.5, 9 - Chapter 6 Class 12 - Application of Derivatives
Last updated at Nov. 23, 2021 by Teachoo
This question is similar to Ex 6.5, 9 - Chapter 6 Class 12 - Application of Derivatives
Transcript
Question 26 The maximum value of sin x . cos x is (A) 1/4 (B) 1/2 (C) β2 (D) 2 β2 Let f(π)=sinβ‘π₯βcosβ‘π₯ =(2 sinβ‘π₯ cosβ‘π₯)/2 =(πππ ππ)/π Since, βπβ€πππ π½β€π Putting π=2π₯ β1β€sinβ‘2π₯β€1 Dividing by 2 β1/2β€(π ππ 2π₯)/2β€1/2 βπ/πβ€π(π)β€π/π β΄ Maximum value of π(π₯) is π/π. So, the correct answer is (B).
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